How many photons are emitted by the antenna every second

Log in. How many photons per second are emitted by the antenna of a microwave oven, if its power output is 1. We're asked to calculate how many photons per second are admitted by the antenna of a microwave oven. If its power output is one killer, what? Which is one times 10 to the third? What's and has If you Quincy of mega hurts, which is attempts tend to the sixth hurt. So first we need to solve for how much energy this antenna is putting out.

So we have energy equals planks, constant times, frequency now planks constant. We want to you use in jewels. So I'm gonna going to use 6. And this gives me an energy of 1. Jules, because the seconds cancel out with these hurts. And again, our power is equal to our energy per unit of time.

So if we rearranged this to get won over tea by itself, this is going to give us a number of photons per second, so our power output, we said, was one times 10 to the third and our energy.

We calculated to be 1. A kHz AM radio station broadcasts with a power of 20 kW. How many photo… An FM radio transmitter has a power output of kW and operates at a frequ… The po… A radio station broadcasts at a frequency of How many photons per second are emitted by a 7. Problem Some satellites use nuclear power. View Full Video Already have an account? Kristela G. Problem 31 Medium Difficulty How many photons per second are emitted by the antenna of a microwave oven, if its power output is 1.

Topics Quantum Physics. Discussion You must be signed in to discuss. Top Physics Educators Christina K. Andy C. University of Michigan - Ann Arbor. Video Transcript. A microwave oven has a power of 1 kilowatt and uses a frequency of megahertz and the question is, how many photons are emitted per second by this microwave? Now the energy per photon is Planck's constant times the frequency of the photon; that's equation [ The total energy emitted by the microwave is the energy per photon multiplied by the total number of photons.

And this can be substituted in place of total energy in our expression for the power, which is energy per time and we'll have energy per photon multiplied by the number of photons per time.

And it's this n over t that we are interested in— the number of photons per time— and that'll be photons per second if we choose our units for everything else correctly. And energy per photon we'll replace with Planck's constant times frequency from here. And so multiply both sides by 1 over hf and multiply this by 1 over hf.

And so we have power over Planck's constant times frequency is the number of photons divided by time. So that's 1 times 10 to the 3 watts, which I could write instead as joules per second and then divide it by 6.